Ready to unlock your full learning experience? Start today - and unlock your math superpower! Finally master math - for real Full access to the entire curriculum Video tutorials that actually work The fastest way to get a better math grade Unlock now How to Multiply Fractions with Variables       When multiplying fractions , I am a fan of factorizing  and canceling common factors instead of multiplying and then simplifying. 
     The reason for this is that it makes the calculations much easier, and I like it when things are easy. By cross-canceling when possible instead of expanding the parentheses, the calculations become simpler and less messy. 
     Here you will learn to multiply fractions with variables by factorizing and cross-canceling. Beware that you can only  cancel factors that are on both sides of the fraction bar. 
             
 Multiplication  Through  Canceling             1.            Factorize         the         numerators.               2.            Factorize         the         denominators.               3.            Cancel         common         factors.               4.            Find         the         answer.         
                                                                                                                                                                                                                                                    Evaluate  x  +  1   x  +  2   ⋅  2 x  +  4    3 x  +  3   
                                                                                          
                                                                                                                                                                                                                                           You factorize and cross-cancel in this way: 
                               x  +  1   x  +  2   ⋅ 2 x  +  4    3 x  +  3                                 =    ( x  +  1 )        ( x  +  2 )     ⋅ 2   ( x  +  2 )      3   ( x  +  1 )                                                                                                                                                      =  ( x  +  1 )    ( x  +  2 )   ⋅ 2 ( x  +  2 )    3 ( x  +  1 )                                                                                                                                                  =  2    3                                                                                                                                                                                                                                                                                                                                                                                                                                                                      Evaluate  2 x  +  6    x  +  3    ⋅  x 2   −  9     x  +  3     
                                                                                          
                                                                                                                                                                                                                                           You factorize using the third algebraic identity of quadratic expressions , and then you cancel and multiply like this:  
     2 x  +  6    x  +  3    ⋅ x 2   −  9     x  +  3                        =                                      2   ( x  +  3 )        ( x  +  3 )      ⋅ ( x  +  3 )     ( x  −  3 )            ( x  +  3 )                    =                                      2 ( x  +  3 )    ( x  +  3 )    ⋅ ( x  +  3 )   ( x  −  3 )          ( x  +  3 )                =                                      2   ( x  −  3 )                                 =                                      2 x  −  6                                                                                                               
                            2 x  +  6    x  +  3    ⋅ x 2   −  9     x  +  3                             =  2   ( x  +  3 )         ( x  +  3 )      ⋅ ( x  +  3 )     ( x  −  3 )            ( x  +  3 )                                                                                                                                      =  2 ( x  +  3 )     ( x  +  3 )    ⋅ ( x  +  3 )   ( x  −  3 )          ( x  +  3 )                                                                                                                                  =  2   ( x  −  3 )                                                                                                                                                   =  2 x  −  6                                                                                
                                                                                                                                                                                                                                                               Evaluate  x 2   −  1    x  +  5   ⋅  x 2   −  2 5     x  −  1     
                                                                                          
                                                                                                                                                                                                                                           Use the third algebraic identity of quadratic expressions to factorize, and then cross-cancel and multiply in this manner:  
     x 2   −  1    x  +  5    ⋅ x 2   −  2 5     x  −  1                               =                                                ( x  −  1 )     ( x  +  1 )           ( x  +  5 )         ⋅ ( x  +  5 )     ( x  −  5 )            ( x  −  1 )                    =                                              ( x  −  1 )   ( x  +  1 )         ( x  +  5 )       ⋅ ( x  +  5 )   ( x  −  5 )          ( x  −  1 )                =                                                ( x  +  1 )     ( x  −  5 )                                 =                                              x 2   −  5 x  +  x  −  5                             =                                              x 2   −  4 x  −  5                                                                                                        
                       x 2   −  1    x  +  5    ⋅ x 2   −  2 5     x  −  1                         =    ( x  −  1 )     ( x  +  1 )            ( x  +  5 )         ⋅ ( x  +  5 )     ( x  −  5 )            ( x  −  1 )                                                                                                                  =  ( x  −  1 )   ( x  +  1 )          ( x  +  5 )       ⋅ ( x  +  5 )   ( x  −  5 )          ( x  −  1 )                                                                                                               =    ( x  +  1 )     ( x  −  5 )                                                                                                                                =  x 2   −  5 x  +  x  −  5                                                                                                                           =  x 2   −  4 x  −  5                                                                      
                                                                                                                                                                                                                                                               Evaluate  2 x 2   −  3 2     x  −  4     ⋅   x  +  5    2   ( x 2   −  2 5 )   
                                                                                          
                                                                                                                                                                                                                                           You factorize with the help of the third algebraic identity of quadratic expressions, and then you cancel and multiply the fractions in this way:  
                                                                =     2 x 2   −  3 2     x  −  4     ⋅   x  +  5    2   ( x 2   −  2 5 )                                                                                                                                            =  2   ( x 2   −  1 6 )          ( x  −  4 )       ⋅    ( x  +  5 )      2   ( x  +  5 )     ( x  −  5 )                                                                                                                                     =  2   ( x  +  4 )  ( x  −  4 )          ( x  −  4 )        ⋅    ( x  +  5 )    2 ( x  +  5 )   ( x  −  5 )                                                                                                                             =    ( x  +  4 )   ⋅   1      ( x  −  5 )                                                                                                                                                    =  x  +  4    x  −  5                                                                                                     
                  2 x 2   −  3 2     x  −  4     ⋅   x  +  5    2   ( x 2   −  2 5 )                   =  2   ( x 2   −  1 6 )          ( x  −  4 )       ⋅    ( x  +  5 )      2   ( x  +  5 )     ( x  −  5 )                                                                                                     =  2   ( x  +  4 )  ( x  −  4 )          ( x  −  4 )        ⋅    ( x  +  5 )    2 ( x  +  5 )   ( x  −  5 )                                                                                             =    ( x  +  4 )   ⋅   1      ( x  −  5 )                                                                                                                     =  x  +  4    x  −  5